6(3z-1)=8(z+6)

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Solution for 6(3z-1)=8(z+6) equation:



6(3z-1)=8(z+6)
We move all terms to the left:
6(3z-1)-(8(z+6))=0
We multiply parentheses
18z-(8(z+6))-6=0
We calculate terms in parentheses: -(8(z+6)), so:
8(z+6)
We multiply parentheses
8z+48
Back to the equation:
-(8z+48)
We get rid of parentheses
18z-8z-48-6=0
We add all the numbers together, and all the variables
10z-54=0
We move all terms containing z to the left, all other terms to the right
10z=54
z=54/10
z=5+2/5

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