6(3z-2)-13=z+9

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Solution for 6(3z-2)-13=z+9 equation: 



6(3z-2)-13=z+9

We move all terms to the left:

6(3z-2)-13-(z+9)=0

We multiply parentheses

18z-(z+9)-12-13=0

We get rid of parentheses

18z-z-9-12-13=0

We add all the numbers together, and all the variables

17z-34=0

We move all terms containing z to the left, all other terms to the right

17z=34

z=34/17

z=2

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