6(3z-6)+3=3z-15

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Solution for 6(3z-6)+3=3z-15 equation: 



6(3z-6)+3=3z-15

We move all terms to the left:

6(3z-6)+3-(3z-15)=0

We multiply parentheses

18z-(3z-15)-36+3=0

We get rid of parentheses

18z-3z+15-36+3=0

We add all the numbers together, and all the variables

15z-18=0

We move all terms containing z to the left, all other terms to the right

15z=18

z=18/15

z=1+1/5

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