6(4)+2(n-3)=15

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Solution for 6(4)+2(n-3)=15 equation: 



6(4)+2(n-3)=15

We move all terms to the left:

6(4)+2(n-3)-(15)=0

We add all the numbers together, and all the variables

2(n-3)+49=0

We multiply parentheses

2n-6+49=0

We add all the numbers together, and all the variables

2n+43=0

We move all terms containing n to the left, all other terms to the right

2n=-43

n=-43/2

n=-21+1/2

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