6(4+2b)+7b=157

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Solution for 6(4+2b)+7b=157 equation: 



6(4+2b)+7b=157

We move all terms to the left:

6(4+2b)+7b-(157)=0

We add all the numbers together, and all the variables

6(2b+4)+7b-157=0

We add all the numbers together, and all the variables

7b+6(2b+4)-157=0

We multiply parentheses

7b+12b+24-157=0

We add all the numbers together, and all the variables

19b-133=0

We move all terms containing b to the left, all other terms to the right

19b=133

b=133/19

b=7

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