6(4+2k)=3(k+8)

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Solution for 6(4+2k)=3(k+8) equation: 



6(4+2k)=3(k+8)

We move all terms to the left:

6(4+2k)-(3(k+8))=0

We add all the numbers together, and all the variables

6(2k+4)-(3(k+8))=0

We multiply parentheses

12k-(3(k+8))+24=0



We calculate terms in parentheses: -(3(k+8)), so:

3(k+8)

We multiply parentheses

3k+24

Back to the equation:

-(3k+24)



We get rid of parentheses

12k-3k-24+24=0

We add all the numbers together, and all the variables

9k=0

k=0/9

k=0

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