6(4+2x)=4(2x-1)+4(x+3)

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Solution for 6(4+2x)=4(2x-1)+4(x+3) equation:


Simplifying
6(4 + 2x) = 4(2x + -1) + 4(x + 3)
(4 * 6 + 2x * 6) = 4(2x + -1) + 4(x + 3)
(24 + 12x) = 4(2x + -1) + 4(x + 3)

Reorder the terms:
24 + 12x = 4(-1 + 2x) + 4(x + 3)
24 + 12x = (-1 * 4 + 2x * 4) + 4(x + 3)
24 + 12x = (-4 + 8x) + 4(x + 3)

Reorder the terms:
24 + 12x = -4 + 8x + 4(3 + x)
24 + 12x = -4 + 8x + (3 * 4 + x * 4)
24 + 12x = -4 + 8x + (12 + 4x)

Reorder the terms:
24 + 12x = -4 + 12 + 8x + 4x

Combine like terms: -4 + 12 = 8
24 + 12x = 8 + 8x + 4x

Combine like terms: 8x + 4x = 12x
24 + 12x = 8 + 12x

Add '-12x' to each side of the equation.
24 + 12x + -12x = 8 + 12x + -12x

Combine like terms: 12x + -12x = 0
24 + 0 = 8 + 12x + -12x
24 = 8 + 12x + -12x

Combine like terms: 12x + -12x = 0
24 = 8 + 0
24 = 8

Solving
24 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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