6(4+a)-12=4(a+3)+2a

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Solution for 6(4+a)-12=4(a+3)+2a equation: 



6(4+a)-12=4(a+3)+2a

We move all terms to the left:

6(4+a)-12-(4(a+3)+2a)=0

We add all the numbers together, and all the variables

6(a+4)-(4(a+3)+2a)-12=0

We multiply parentheses

6a-(4(a+3)+2a)+24-12=0



We calculate terms in parentheses: -(4(a+3)+2a), so:

4(a+3)+2a

We add all the numbers together, and all the variables

2a+4(a+3)

We multiply parentheses

2a+4a+12

We add all the numbers together, and all the variables

6a+12

Back to the equation:

-(6a+12)



We add all the numbers together, and all the variables

6a-(6a+12)+12=0

We get rid of parentheses

6a-6a-12+12=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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