6(4+c)-3=4(c-3)+2c

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Solution for 6(4+c)-3=4(c-3)+2c equation: 



6(4+c)-3=4(c-3)+2c

We move all terms to the left:

6(4+c)-3-(4(c-3)+2c)=0

We add all the numbers together, and all the variables

6(c+4)-(4(c-3)+2c)-3=0

We multiply parentheses

6c-(4(c-3)+2c)+24-3=0



We calculate terms in parentheses: -(4(c-3)+2c), so:

4(c-3)+2c

We add all the numbers together, and all the variables

2c+4(c-3)

We multiply parentheses

2c+4c-12

We add all the numbers together, and all the variables

6c-12

Back to the equation:

-(6c-12)



We add all the numbers together, and all the variables

6c-(6c-12)+21=0

We get rid of parentheses

6c-6c+12+21=0

We add all the numbers together, and all the variables

33!=0

There is no solution for this equation

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