6(4+c)=5(1+c)

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Solution for 6(4+c)=5(1+c) equation: 



6(4+c)=5(1+c)

We move all terms to the left:

6(4+c)-(5(1+c))=0

We add all the numbers together, and all the variables

6(c+4)-(5(c+1))=0

We multiply parentheses

6c-(5(c+1))+24=0



We calculate terms in parentheses: -(5(c+1)), so:

5(c+1)

We multiply parentheses

5c+5

Back to the equation:

-(5c+5)



We get rid of parentheses

6c-5c-5+24=0

We add all the numbers together, and all the variables

c+19=0

We move all terms containing c to the left, all other terms to the right

c=-19

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