6(4+c)=5(c+2)

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Solution for 6(4+c)=5(c+2) equation:


Simplifying
6(4 + c) = 5(c + 2)
(4 * 6 + c * 6) = 5(c + 2)
(24 + 6c) = 5(c + 2)

Reorder the terms:
24 + 6c = 5(2 + c)
24 + 6c = (2 * 5 + c * 5)
24 + 6c = (10 + 5c)

Solving
24 + 6c = 10 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
24 + 6c + -5c = 10 + 5c + -5c

Combine like terms: 6c + -5c = 1c
24 + 1c = 10 + 5c + -5c

Combine like terms: 5c + -5c = 0
24 + 1c = 10 + 0
24 + 1c = 10

Add '-24' to each side of the equation.
24 + -24 + 1c = 10 + -24

Combine like terms: 24 + -24 = 0
0 + 1c = 10 + -24
1c = 10 + -24

Combine like terms: 10 + -24 = -14
1c = -14

Divide each side by '1'.
c = -14

Simplifying
c = -14

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