6(4+k)=5(2+k)

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Solution for 6(4+k)=5(2+k) equation: 



6(4+k)=5(2+k)

We move all terms to the left:

6(4+k)-(5(2+k))=0

We add all the numbers together, and all the variables

6(k+4)-(5(k+2))=0

We multiply parentheses

6k-(5(k+2))+24=0



We calculate terms in parentheses: -(5(k+2)), so:

5(k+2)

We multiply parentheses

5k+10

Back to the equation:

-(5k+10)



We get rid of parentheses

6k-5k-10+24=0

We add all the numbers together, and all the variables

k+14=0

We move all terms containing k to the left, all other terms to the right

k=-14

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