6(4+t)-4(t+1)=28-2t

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Solution for 6(4+t)-4(t+1)=28-2t equation: 


Simplifying
6(4 + t) + -4(t + 1) = 28 + -2t
(4 * 6 + t * 6) + -4(t + 1) = 28 + -2t
(24 + 6t) + -4(t + 1) = 28 + -2t

Reorder the terms:
24 + 6t + -4(1 + t) = 28 + -2t
24 + 6t + (1 * -4 + t * -4) = 28 + -2t
24 + 6t + (-4 + -4t) = 28 + -2t

Reorder the terms:
24 + -4 + 6t + -4t = 28 + -2t

Combine like terms: 24 + -4 = 20
20 + 6t + -4t = 28 + -2t

Combine like terms: 6t + -4t = 2t
20 + 2t = 28 + -2t

Solving
20 + 2t = 28 + -2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '2t' to each side of the equation.
20 + 2t + 2t = 28 + -2t + 2t

Combine like terms: 2t + 2t = 4t
20 + 4t = 28 + -2t + 2t

Combine like terms: -2t + 2t = 0
20 + 4t = 28 + 0
20 + 4t = 28

Add '-20' to each side of the equation.
20 + -20 + 4t = 28 + -20

Combine like terms: 20 + -20 = 0
0 + 4t = 28 + -20
4t = 28 + -20

Combine like terms: 28 + -20 = 8
4t = 8

Divide each side by '4'.
t = 2

Simplifying
t = 2

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