6(4+v)+32v=15v

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Solution for 6(4+v)+32v=15v equation: 



6(4+v)+32v=15v

We move all terms to the left:

6(4+v)+32v-(15v)=0

We add all the numbers together, and all the variables

6(v+4)+32v-15v=0

We add all the numbers together, and all the variables

17v+6(v+4)=0

We multiply parentheses

17v+6v+24=0

We add all the numbers together, and all the variables

23v+24=0

We move all terms containing v to the left, all other terms to the right

23v=-24

v=-24/23

v=-1+1/23

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