6(4+y)-3=4(y-3)-2y

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Solution for 6(4+y)-3=4(y-3)-2y equation: 



6(4+y)-3=4(y-3)-2y

We move all terms to the left:

6(4+y)-3-(4(y-3)-2y)=0

We add all the numbers together, and all the variables

6(y+4)-(4(y-3)-2y)-3=0

We multiply parentheses

6y-(4(y-3)-2y)+24-3=0



We calculate terms in parentheses: -(4(y-3)-2y), so:

4(y-3)-2y

We add all the numbers together, and all the variables

-2y+4(y-3)

We multiply parentheses

-2y+4y-12

We add all the numbers together, and all the variables

2y-12

Back to the equation:

-(2y-12)



We add all the numbers together, and all the variables

6y-(2y-12)+21=0

We get rid of parentheses

6y-2y+12+21=0

We add all the numbers together, and all the variables

4y+33=0

We move all terms containing y to the left, all other terms to the right

4y=-33

y=-33/4

y=-8+1/4

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