6(4+y)=8(3-y)=10

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Solution for 6(4+y)=8(3-y)=10 equation:



6(4+y)=8(3-y)=10
We move all terms to the left:
6(4+y)-(8(3-y))=0
We add all the numbers together, and all the variables
6(y+4)-(8(-1y+3))=0
We multiply parentheses
6y-(8(-1y+3))+24=0
We calculate terms in parentheses: -(8(-1y+3)), so:
8(-1y+3)
We multiply parentheses
-8y+24
Back to the equation:
-(-8y+24)
We get rid of parentheses
6y+8y-24+24=0
We add all the numbers together, and all the variables
14y=0
y=0/14
y=0

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