6(4+z)=2z

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Solution for 6(4+z)=2z equation: 



6(4+z)=2z

We move all terms to the left:

6(4+z)-(2z)=0

We add all the numbers together, and all the variables

6(z+4)-2z=0

We add all the numbers together, and all the variables

-2z+6(z+4)=0

We multiply parentheses

-2z+6z+24=0

We add all the numbers together, and all the variables

4z+24=0

We move all terms containing z to the left, all other terms to the right

4z=-24

z=-24/4

z=-6

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