6(4-(5+2x))-2x=-8+2(1-7x)

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Solution for 6(4-(5+2x))-2x=-8+2(1-7x) equation: 



6(4-(5+2x))-2x=-8+2(1-7x)

We move all terms to the left:

6(4-(5+2x))-2x-(-8+2(1-7x))=0

We add all the numbers together, and all the variables

6(4-(2x+5))-2x-(-8+2(-7x+1))=0

We add all the numbers together, and all the variables

-2x+6(4-(2x+5))-(-8+2(-7x+1))=0



We calculate terms in parentheses: -(-8+2(-7x+1)), so:

-8+2(-7x+1)

determiningTheFunctionDomain
2(-7x+1)-8

We multiply parentheses

-14x+2-8

We add all the numbers together, and all the variables

-14x-6

Back to the equation:

-(-14x-6)



We get rid of parentheses

-2x+6(4-(2x+5))+14x+6=0

We add all the numbers together, and all the variables

12x+6(4-(2x+5))+6=0

We move all terms containing x to the left, all other terms to the right

12x+6(4-(2x+5))=-6

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