6(4-2n)=2(n-1)-n

Solution for 6(4-2n)=2(n-1)-n equation:

6(4-2n)=2(n-1)-n

We move all terms to the left:

6(4-2n)-(2(n-1)-n)=0

We add all the numbers together, and all the variables

6(-2n+4)-(2(n-1)-n)=0

We multiply parentheses

-12n-(2(n-1)-n)+24=0


We calculate terms in parentheses: -(2(n-1)-n), so:

2(n-1)-n

We add all the numbers together, and all the variables

-1n+2(n-1)

We multiply parentheses

-1n+2n-2

We add all the numbers together, and all the variables

n-2

Back to the equation:

-(n-2)


We get rid of parentheses

-12n-n+2+24=0

We add all the numbers together, and all the variables

-13n+26=0

We move all terms containing n to the left, all other terms to the right

-13n=-26

n=-26/-13

n=+2