6(4-x)+18x=72

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Solution for 6(4-x)+18x=72 equation:



6(4-x)+18x=72
We move all terms to the left:
6(4-x)+18x-(72)=0
We add all the numbers together, and all the variables
6(-1x+4)+18x-72=0
We add all the numbers together, and all the variables
18x+6(-1x+4)-72=0
We multiply parentheses
18x-6x+24-72=0
We add all the numbers together, and all the variables
12x-48=0
We move all terms containing x to the left, all other terms to the right
12x=48
x=48/12
x=4

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