6(4-x)+18x=72

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Solution for 6(4-x)+18x=72 equation: 



6(4-x)+18x=72

We move all terms to the left:

6(4-x)+18x-(72)=0

We add all the numbers together, and all the variables

6(-1x+4)+18x-72=0

We add all the numbers together, and all the variables

18x+6(-1x+4)-72=0

We multiply parentheses

18x-6x+24-72=0

We add all the numbers together, and all the variables

12x-48=0

We move all terms containing x to the left, all other terms to the right

12x=48

x=48/12

x=4

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