6(4a+5)=2(20a+7)

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Solution for 6(4a+5)=2(20a+7) equation: 



6(4a+5)=2(20a+7)

We move all terms to the left:

6(4a+5)-(2(20a+7))=0

We multiply parentheses

24a-(2(20a+7))+30=0



We calculate terms in parentheses: -(2(20a+7)), so:

2(20a+7)

We multiply parentheses

40a+14

Back to the equation:

-(40a+14)



We get rid of parentheses

24a-40a-14+30=0

We add all the numbers together, and all the variables

-16a+16=0

We move all terms containing a to the left, all other terms to the right

-16a=-16

a=-16/-16

a=1

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