6(4a-3)-9a=5(2a+1)+12

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Solution for 6(4a-3)-9a=5(2a+1)+12 equation: 



6(4a-3)-9a=5(2a+1)+12

We move all terms to the left:

6(4a-3)-9a-(5(2a+1)+12)=0

We add all the numbers together, and all the variables

-9a+6(4a-3)-(5(2a+1)+12)=0

We multiply parentheses

-9a+24a-(5(2a+1)+12)-18=0



We calculate terms in parentheses: -(5(2a+1)+12), so:

5(2a+1)+12

We multiply parentheses

10a+5+12

We add all the numbers together, and all the variables

10a+17

Back to the equation:

-(10a+17)



We add all the numbers together, and all the variables

15a-(10a+17)-18=0

We get rid of parentheses

15a-10a-17-18=0

We add all the numbers together, and all the variables

5a-35=0

We move all terms containing a to the left, all other terms to the right

5a=35

a=35/5

a=7

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