6(4k-4)=3(k+6)

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Solution for 6(4k-4)=3(k+6) equation: 



6(4k-4)=3(k+6)

We move all terms to the left:

6(4k-4)-(3(k+6))=0

We multiply parentheses

24k-(3(k+6))-24=0



We calculate terms in parentheses: -(3(k+6)), so:

3(k+6)

We multiply parentheses

3k+18

Back to the equation:

-(3k+18)



We get rid of parentheses

24k-3k-18-24=0

We add all the numbers together, and all the variables

21k-42=0

We move all terms containing k to the left, all other terms to the right

21k=42

k=42/21

k=2

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