6(4k-5)=39+k

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Solution for 6(4k-5)=39+k equation: 



6(4k-5)=39+k

We move all terms to the left:

6(4k-5)-(39+k)=0

We add all the numbers together, and all the variables

6(4k-5)-(k+39)=0

We multiply parentheses

24k-(k+39)-30=0

We get rid of parentheses

24k-k-39-30=0

We add all the numbers together, and all the variables

23k-69=0

We move all terms containing k to the left, all other terms to the right

23k=69

k=69/23

k=3

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