6(4n+3)=27-5n

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Solution for 6(4n+3)=27-5n equation: 



6(4n+3)=27-5n

We move all terms to the left:

6(4n+3)-(27-5n)=0

We add all the numbers together, and all the variables

6(4n+3)-(-5n+27)=0

We multiply parentheses

24n-(-5n+27)+18=0

We get rid of parentheses

24n+5n-27+18=0

We add all the numbers together, and all the variables

29n-9=0

We move all terms containing n to the left, all other terms to the right

29n=9

n=9/29

n=9/29

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