6(4r+3)=210

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Solution for 6(4r+3)=210 equation: 



6(4r+3)=210

We move all terms to the left:

6(4r+3)-(210)=0

We multiply parentheses

24r+18-210=0

We add all the numbers together, and all the variables

24r-192=0

We move all terms containing r to the left, all other terms to the right

24r=192

r=192/24

r=8

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