6(4r-2)-1=8r+35

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Solution for 6(4r-2)-1=8r+35 equation:



6(4r-2)-1=8r+35
We move all terms to the left:
6(4r-2)-1-(8r+35)=0
We multiply parentheses
24r-(8r+35)-12-1=0
We get rid of parentheses
24r-8r-35-12-1=0
We add all the numbers together, and all the variables
16r-48=0
We move all terms containing r to the left, all other terms to the right
16r=48
r=48/16
r=3

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