6(4r-3)=12

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Solution for 6(4r-3)=12 equation: 



6(4r-3)=12

We move all terms to the left:

6(4r-3)-(12)=0

We multiply parentheses

24r-18-12=0

We add all the numbers together, and all the variables

24r-30=0

We move all terms containing r to the left, all other terms to the right

24r=30

r=30/24

r=1+1/4

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