6(4t+1)-8=(t+1)

Solution for 6(4t+1)-8=(t+1) equation:

6(4t+1)-8=(t+1)

We move all terms to the left:

6(4t+1)-8-((t+1))=0

We multiply parentheses

24t-((t+1))+6-8=0


We calculate terms in parentheses: -((t+1)), so:

(t+1)

We get rid of parentheses

t+1

Back to the equation:

-(t+1)


We add all the numbers together, and all the variables

24t-(t+1)-2=0

We get rid of parentheses

24t-t-1-2=0

We add all the numbers together, and all the variables

23t-3=0

We move all terms containing t to the left, all other terms to the right

23t=3

t=3/23

t=3/23