6(4v+8)=4v-32

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Solution for 6(4v+8)=4v-32 equation: 



6(4v+8)=4v-32

We move all terms to the left:

6(4v+8)-(4v-32)=0

We multiply parentheses

24v-(4v-32)+48=0

We get rid of parentheses

24v-4v+32+48=0

We add all the numbers together, and all the variables

20v+80=0

We move all terms containing v to the left, all other terms to the right

20v=-80

v=-80/20

v=-4

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