6(4x*7x)=x+33

Solution for 6(4x*7x)=x+33 equation:

6(4x*7x)=x+33

We move all terms to the left:

6(4x*7x)-(x+33)=0

We add all the numbers together, and all the variables

6(+4x*7x)-(x+33)=0

We multiply parentheses

168x^2-(x+33)=0

We get rid of parentheses

168x^2-x-33=0

We add all the numbers together, and all the variables

168x^2-1x-33=0

a = 168; b = -1; c = -33;
Δ = b2-4ac
Δ = -12-4·168·(-33)
Δ = 22177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{22177}}{2*168}=\frac{1-\sqrt{22177}}{336}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{22177}}{2*168}=\frac{1+\sqrt{22177}}{336}
$