6(4x+1)=3(2x+56)

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Solution for 6(4x+1)=3(2x+56) equation: 



6(4x+1)=3(2x+56)

We move all terms to the left:

6(4x+1)-(3(2x+56))=0

We multiply parentheses

24x-(3(2x+56))+6=0



We calculate terms in parentheses: -(3(2x+56)), so:

3(2x+56)

We multiply parentheses

6x+168

Back to the equation:

-(6x+168)



We get rid of parentheses

24x-6x-168+6=0

We add all the numbers together, and all the variables

18x-162=0

We move all terms containing x to the left, all other terms to the right

18x=162

x=162/18

x=9

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