6(4x+5)=(4x+12)

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Solution for 6(4x+5)=(4x+12) equation: 



6(4x+5)=(4x+12)

We move all terms to the left:

6(4x+5)-((4x+12))=0

We multiply parentheses

24x-((4x+12))+30=0



We calculate terms in parentheses: -((4x+12)), so:

(4x+12)

We get rid of parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

24x-4x-12+30=0

We add all the numbers together, and all the variables

20x+18=0

We move all terms containing x to the left, all other terms to the right

20x=-18

x=-18/20

x=-9/10

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