6(4x+5)=7(2x+3)

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Solution for 6(4x+5)=7(2x+3) equation:



6(4x+5)=7(2x+3)
We move all terms to the left:
6(4x+5)-(7(2x+3))=0
We multiply parentheses
24x-(7(2x+3))+30=0
We calculate terms in parentheses: -(7(2x+3)), so:
7(2x+3)
We multiply parentheses
14x+21
Back to the equation:
-(14x+21)
We get rid of parentheses
24x-14x-21+30=0
We add all the numbers together, and all the variables
10x+9=0
We move all terms containing x to the left, all other terms to the right
10x=-9
x=-9/10
x=-9/10

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