6(4x-2)+7x=7(3x+6)-6x

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Solution for 6(4x-2)+7x=7(3x+6)-6x equation: 



6(4x-2)+7x=7(3x+6)-6x

We move all terms to the left:

6(4x-2)+7x-(7(3x+6)-6x)=0

We add all the numbers together, and all the variables

7x+6(4x-2)-(7(3x+6)-6x)=0

We multiply parentheses

7x+24x-(7(3x+6)-6x)-12=0



We calculate terms in parentheses: -(7(3x+6)-6x), so:

7(3x+6)-6x

We add all the numbers together, and all the variables

-6x+7(3x+6)

We multiply parentheses

-6x+21x+42

We add all the numbers together, and all the variables

15x+42

Back to the equation:

-(15x+42)



We add all the numbers together, and all the variables

31x-(15x+42)-12=0

We get rid of parentheses

31x-15x-42-12=0

We add all the numbers together, and all the variables

16x-54=0

We move all terms containing x to the left, all other terms to the right

16x=54

x=54/16

x=3+3/8

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