6(4x-3)+3(15-5x)=2(4x+2)-2

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Solution for 6(4x-3)+3(15-5x)=2(4x+2)-2 equation: 



6(4x-3)+3(15-5x)=2(4x+2)-2

We move all terms to the left:

6(4x-3)+3(15-5x)-(2(4x+2)-2)=0

We add all the numbers together, and all the variables

6(4x-3)+3(-5x+15)-(2(4x+2)-2)=0

We multiply parentheses

24x-15x-(2(4x+2)-2)-18+45=0



We calculate terms in parentheses: -(2(4x+2)-2), so:

2(4x+2)-2

We multiply parentheses

8x+4-2

We add all the numbers together, and all the variables

8x+2

Back to the equation:

-(8x+2)



We add all the numbers together, and all the variables

9x-(8x+2)+27=0

We get rid of parentheses

9x-8x-2+27=0

We add all the numbers together, and all the variables

x+25=0

We move all terms containing x to the left, all other terms to the right

x=-25

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