6(4x-3)=4(8x+4)-10

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Solution for 6(4x-3)=4(8x+4)-10 equation: 



6(4x-3)=4(8x+4)-10

We move all terms to the left:

6(4x-3)-(4(8x+4)-10)=0

We multiply parentheses

24x-(4(8x+4)-10)-18=0



We calculate terms in parentheses: -(4(8x+4)-10), so:

4(8x+4)-10

We multiply parentheses

32x+16-10

We add all the numbers together, and all the variables

32x+6

Back to the equation:

-(32x+6)



We get rid of parentheses

24x-32x-6-18=0

We add all the numbers together, and all the variables

-8x-24=0

We move all terms containing x to the left, all other terms to the right

-8x=24

x=24/-8

x=-3

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