6(4x-3)=4(8x+4)-10

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Solution for 6(4x-3)=4(8x+4)-10 equation:



6(4x-3)=4(8x+4)-10
We move all terms to the left:
6(4x-3)-(4(8x+4)-10)=0
We multiply parentheses
24x-(4(8x+4)-10)-18=0
We calculate terms in parentheses: -(4(8x+4)-10), so:
4(8x+4)-10
We multiply parentheses
32x+16-10
We add all the numbers together, and all the variables
32x+6
Back to the equation:
-(32x+6)
We get rid of parentheses
24x-32x-6-18=0
We add all the numbers together, and all the variables
-8x-24=0
We move all terms containing x to the left, all other terms to the right
-8x=24
x=24/-8
x=-3

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