6(4x-3)=x+15

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Solution for 6(4x-3)=x+15 equation: 



6(4x-3)=x+15

We move all terms to the left:

6(4x-3)-(x+15)=0

We multiply parentheses

24x-(x+15)-18=0

We get rid of parentheses

24x-x-15-18=0

We add all the numbers together, and all the variables

23x-33=0

We move all terms containing x to the left, all other terms to the right

23x=33

x=33/23

x=1+10/23

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