6(4x-5)+4(11-2x)-5(3x+4)=-17

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Solution for 6(4x-5)+4(11-2x)-5(3x+4)=-17 equation: 



6(4x-5)+4(11-2x)-5(3x+4)=-17

We move all terms to the left:

6(4x-5)+4(11-2x)-5(3x+4)-(-17)=0

We add all the numbers together, and all the variables

6(4x-5)+4(-2x+11)-5(3x+4)-(-17)=0

We add all the numbers together, and all the variables

6(4x-5)+4(-2x+11)-5(3x+4)+17=0

We multiply parentheses

24x-8x-15x-30+44-20+17=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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