6(4x-5)=3x+33

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Solution for 6(4x-5)=3x+33 equation: 



6(4x-5)=3x+33

We move all terms to the left:

6(4x-5)-(3x+33)=0

We multiply parentheses

24x-(3x+33)-30=0

We get rid of parentheses

24x-3x-33-30=0

We add all the numbers together, and all the variables

21x-63=0

We move all terms containing x to the left, all other terms to the right

21x=63

x=63/21

x=3

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