6(4x-7)-4=6(x-3)+62

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Solution for 6(4x-7)-4=6(x-3)+62 equation: 



6(4x-7)-4=6(x-3)+62

We move all terms to the left:

6(4x-7)-4-(6(x-3)+62)=0

We multiply parentheses

24x-(6(x-3)+62)-42-4=0



We calculate terms in parentheses: -(6(x-3)+62), so:

6(x-3)+62

We multiply parentheses

6x-18+62

We add all the numbers together, and all the variables

6x+44

Back to the equation:

-(6x+44)



We add all the numbers together, and all the variables

24x-(6x+44)-46=0

We get rid of parentheses

24x-6x-44-46=0

We add all the numbers together, and all the variables

18x-90=0

We move all terms containing x to the left, all other terms to the right

18x=90

x=90/18

x=5

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