6(4x-8)-2=6(x-4)+100

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Solution for 6(4x-8)-2=6(x-4)+100 equation:



6(4x-8)-2=6(x-4)+100
We move all terms to the left:
6(4x-8)-2-(6(x-4)+100)=0
We multiply parentheses
24x-(6(x-4)+100)-48-2=0
We calculate terms in parentheses: -(6(x-4)+100), so:
6(x-4)+100
We multiply parentheses
6x-24+100
We add all the numbers together, and all the variables
6x+76
Back to the equation:
-(6x+76)
We add all the numbers together, and all the variables
24x-(6x+76)-50=0
We get rid of parentheses
24x-6x-76-50=0
We add all the numbers together, and all the variables
18x-126=0
We move all terms containing x to the left, all other terms to the right
18x=126
x=126/18
x=7

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