6(4x-9)-3=6(x-2)+45

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Solution for 6(4x-9)-3=6(x-2)+45 equation: 



6(4x-9)-3=6(x-2)+45

We move all terms to the left:

6(4x-9)-3-(6(x-2)+45)=0

We multiply parentheses

24x-(6(x-2)+45)-54-3=0



We calculate terms in parentheses: -(6(x-2)+45), so:

6(x-2)+45

We multiply parentheses

6x-12+45

We add all the numbers together, and all the variables

6x+33

Back to the equation:

-(6x+33)



We add all the numbers together, and all the variables

24x-(6x+33)-57=0

We get rid of parentheses

24x-6x-33-57=0

We add all the numbers together, and all the variables

18x-90=0

We move all terms containing x to the left, all other terms to the right

18x=90

x=90/18

x=5

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