6(4x-9)-4=6(x-3)+50

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Solution for 6(4x-9)-4=6(x-3)+50 equation:



6(4x-9)-4=6(x-3)+50
We move all terms to the left:
6(4x-9)-4-(6(x-3)+50)=0
We multiply parentheses
24x-(6(x-3)+50)-54-4=0
We calculate terms in parentheses: -(6(x-3)+50), so:
6(x-3)+50
We multiply parentheses
6x-18+50
We add all the numbers together, and all the variables
6x+32
Back to the equation:
-(6x+32)
We add all the numbers together, and all the variables
24x-(6x+32)-58=0
We get rid of parentheses
24x-6x-32-58=0
We add all the numbers together, and all the variables
18x-90=0
We move all terms containing x to the left, all other terms to the right
18x=90
x=90/18
x=5

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