6(4x-9)-5=6(x-3)+49

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Solution for 6(4x-9)-5=6(x-3)+49 equation: 



6(4x-9)-5=6(x-3)+49

We move all terms to the left:

6(4x-9)-5-(6(x-3)+49)=0

We multiply parentheses

24x-(6(x-3)+49)-54-5=0



We calculate terms in parentheses: -(6(x-3)+49), so:

6(x-3)+49

We multiply parentheses

6x-18+49

We add all the numbers together, and all the variables

6x+31

Back to the equation:

-(6x+31)



We add all the numbers together, and all the variables

24x-(6x+31)-59=0

We get rid of parentheses

24x-6x-31-59=0

We add all the numbers together, and all the variables

18x-90=0

We move all terms containing x to the left, all other terms to the right

18x=90

x=90/18

x=5

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