6(4y+20)=2(-8y-17)-6

Solution for 6(4y+20)=2(-8y-17)-6 equation:

6(4y+20)=2(-8y-17)-6

We move all terms to the left:

6(4y+20)-(2(-8y-17)-6)=0

We multiply parentheses

24y-(2(-8y-17)-6)+120=0


We calculate terms in parentheses: -(2(-8y-17)-6), so:

2(-8y-17)-6

We multiply parentheses

-16y-34-6

We add all the numbers together, and all the variables

-16y-40

Back to the equation:

-(-16y-40)


We get rid of parentheses

24y+16y+40+120=0

We add all the numbers together, and all the variables

40y+160=0

We move all terms containing y to the left, all other terms to the right

40y=-160

y=-160/40

y=-4