6(4y+3)+16=4(5y-2)+12

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Solution for 6(4y+3)+16=4(5y-2)+12 equation:



6(4y+3)+16=4(5y-2)+12
We move all terms to the left:
6(4y+3)+16-(4(5y-2)+12)=0
We multiply parentheses
24y-(4(5y-2)+12)+18+16=0
We calculate terms in parentheses: -(4(5y-2)+12), so:
4(5y-2)+12
We multiply parentheses
20y-8+12
We add all the numbers together, and all the variables
20y+4
Back to the equation:
-(20y+4)
We add all the numbers together, and all the variables
24y-(20y+4)+34=0
We get rid of parentheses
24y-20y-4+34=0
We add all the numbers together, and all the variables
4y+30=0
We move all terms containing y to the left, all other terms to the right
4y=-30
y=-30/4
y=-7+1/2

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