6(4y-1)/7=4y-2

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Solution for 6(4y-1)/7=4y-2 equation: 


y in (-oo:+oo)

(6*(4*y-1))/7 = 4*y-2 // - 4*y-2

(6*(4*y-1))/7-(4*y)+2 = 0

(6*(4*y-1))/7-4*y+2 = 0

(6*(4*y-1))/7+(-4*7*y)/7+(2*7)/7 = 0

6*(4*y-1)-4*7*y+2*7 = 0

14-4*y-6 = 0

8-4*y = 0

(8-4*y)/7 = 0

(8-4*y)/7 = 0 // * 7

8-4*y = 0

8-4*y = 0 // - 8

-4*y = -8 // : -4

y = -8/(-4)

y = 2

y = 2

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