6(4z+2)-20z=40

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Solution for 6(4z+2)-20z=40 equation: 



6(4z+2)-20z=40

We move all terms to the left:

6(4z+2)-20z-(40)=0

We add all the numbers together, and all the variables

-20z+6(4z+2)-40=0

We multiply parentheses

-20z+24z+12-40=0

We add all the numbers together, and all the variables

4z-28=0

We move all terms containing z to the left, all other terms to the right

4z=28

z=28/4

z=7

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