6(4z+2)=3(4z+4)

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Solution for 6(4z+2)=3(4z+4) equation: 



6(4z+2)=3(4z+4)

We move all terms to the left:

6(4z+2)-(3(4z+4))=0

We multiply parentheses

24z-(3(4z+4))+12=0



We calculate terms in parentheses: -(3(4z+4)), so:

3(4z+4)

We multiply parentheses

12z+12

Back to the equation:

-(12z+12)



We get rid of parentheses

24z-12z-12+12=0

We add all the numbers together, and all the variables

12z=0

z=0/12

z=0

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